0=-3x^2+600x

Solution for 0=-3x^2+600x equation:

0=-3x^2+600x

We move all terms to the left:

0-(-3x^2+600x)=0

We add all the numbers together, and all the variables

-(-3x^2+600x)=0

We get rid of parentheses

3x^2-600x=0

a = 3; b = -600; c = 0;
Δ = b2-4ac
Δ = -6002-4·3·0
Δ = 360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{360000}=600$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-600}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+600}{2*3}=\frac{1200}{6}
=200
$